Tangente
f ( x ) = t ( x ) | koordinaten gleich
f ´( x ) = t ´( x ) | Steigung gleich
f ( x ) = ( 3/5) * x^2 + (6/5) * x -9/5
f ( 1 ) = 0
f ´ ( x ) = ( 6/5) * x + (6/5)
f ´( 1 ) = 12 / 5
t ( x ) = m * x + b
m = f ´ ( x )
m = 12 / 5
t ( x ) = 12 / 5 * x + b
t ( 1 ) = 12 / 5 * 1 + b = 0
b = -12/5
t ( x ) = 12/5 * x - 12/5
Normale
( x | y )
( 1 | 0 )
Steigung
mt = - 1 / m
mt = - 1 / / (12/5)
mt = - 5 / 12
0 = - 5/12 * 1 + b
b = 5/12
Normale = - 5/12 * x + 5/12