a) 4x²+4xm+m² = (2x)^2 + 2*2x*m + m^2 = (2x+m)^2
b) 9/25 m²n²+12/15mn²r+4/9n²r² = (3/5 mn)^2 + 12/15 mn^2 r + (2/3 nr)^2 = (3/5 mn + 2/3 nr)^2
c) x²+x-20 |pq-Formel anwenden um die Nullstellen zu finden
x1 = -5 und x2 = 4
Linearfaktordarstellung:
x^2+x-20 = (x+5) * (x-4)
d)4/9s²-9/16t² = (2/3s)^2 - (3/4t)^2 = (2/3s - 3/4t) * (2/3s + 3/4t)
Grüße