Weg über Ausrechnen von b:
\(c²= a²+b²-2abcos(γ)\)
\(10,5²= 4,7²+b²-2*4,7*b*cos(107°)\)
\(b²-2*4,7*b*cos(107°)=10,5²-4,7^2 =88,16 \)
\((b-4,7*cos(107°))^2 =88,16 +(4,7*cos(107°))^2=90.05|\sqrt{}\)
1.)\(b-4,7*cos(107°) ≈9,5\)
\(b₁ ≈8,13\)
2.)\(b-4,7*cos(107°) ≈-9,5\)
\(b₂ ≈-10,8\) Negative Strecken gibt es nicht.