Question

 $$ 127 + x³ = ( x + 1 ) ³  $$

Answer 1

127 + x³ = ( x + 1 ) ³

127 +x^3 =  x^3+3 x^2+3x+1  |-x^3

127  =  3 x^2+3x+1  |-127

0= 3 x^2+3x-126  |:3

0= x^2 +x - 42 ->PQ-Formel

0= -1/2 ± √(1/4 +168/4)

0= -1/2 ± 13/2

x₁= 6

x₂= -7

Answer 2

127+x^3=(x+1)^3

127+x^3=x^3+3x^2+3x+1

0=3x^2+3x-126

0=x^2+x-42

0=(x+7)*(x-6)

x=-7

x=6

Answer 3

127+x^3= x^3+3x^2+3x+1

3x^2+3x-126=0

x^2+x-42=0

pq-Formel anwenden:

...