für den Fall r^> >> r^>'
1/abs(r^>-r^>')=sum(1/n! (-r^>'*\Nabla)^n 1/r,n=0,\inf)
1/abs(r^>-r^>')=1/r+(-r^>'*\Nabla) 1/r+1/2! (r^>'*\Nabla)^2 1/r+....
1/abs(r^>-r^>')=1/r+(r^>*r^>')/r^3+1/2 (3(r^>*r^>')^2/r^5-r'^2/r^3)+..Uebungsblatt 3.pdf (0,2 MB)
Es ist die Nummer 4 b)
