1) kann man nur mit einem GTR ausrechenen oder durch probieren und dann die Näherungsformeln von Newton (Tangentenverfahren) oder Regula falsi (Sehenverfahren) anwenden
f(x)=-10=...
0=-0,4*x³+2*x²+0,4*x+10-9
0=-0,4*x³+2*x²+0,4*x+9
Mit meinem GTR (Casio)
x=5,5502... ist die einzigste reelle Nullstelle (Schnittstelle mit der x-Achse)
dann noch 2 konjugiert komplexe Lösungen
z1=-0,275..+i 1,9945.. und z2=-0,275..-i 1,9945.. siehe Mathe-Formelbuch,komplexe Zahlen
1 Schritt: Immer den Graphen zeichnen,damit man einen Überblick hat.
3) Minimum und Maximum bestimmen,Kurvendiskussion durchführen
Infos,vergrößern und/oder herunterladen
Text erkannt:
"
" A veres, are sen arere nercolor man heranger are and not
in and the reacher and and and and and and and and and and and and and and and and and and and and and and
and and and and and and and and and
perencents and are are are are are are are are are are are are are are are are are are are are are are are are are are are
reacherent and and and and and and and and and and and and and and and and and and and
and and and and and and and and and and
and and and and and and 8 and
and and and 8 and 4 and
and and 8 and 4 and
and and 8 and 4 and
and and 1 and 1 and
and and and 1 and
and and are are are are are
and and 1 and
and and 1 and
and 1 and
and 1 and
and 1 and
and and
and and and
and and and are are are are are are are are are are are
and and and and
and and and
and and
and and and and
and and
Darsing
are
\( \begin{array}{ll}\text { (年) } \frac{1}{3} & \text { (年) } 4,5,5 \\ \text { (年) } \frac{0}{5} & \text { (年) } \frac{0}{5}\end{array} \)
Ind. since and